24.6^2+b^2=91.8^2

Solution for 24.6^2+b^2=91.8^2 equation:

24.6^2+b^2=91.8^2

We move all terms to the left:

24.6^2+b^2-(91.8^2)=0

We add all the numbers together, and all the variables

b^2-7822.08=0

a = 1; b = 0; c = -7822.08;
Δ = b2-4ac
Δ = 02-4·1·(-7822.08)
Δ = 31288.32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{31288.32}}{2*1}=\frac{0-\sqrt{31288.32}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{31288.32}}{2*1}=\frac{0+\sqrt{31288.32}}{2}
=\frac{\sqrt{}}{2}
$